Input Impedance of Antenna

Definition: The input impedance of antenna is basically the impedance offered by the antenna at its terminals. It is defined as the ratio of voltage to the current across the two input terminals of the antenna. Generally, the antenna impedance is given as:

eq1

We have already discussed in our previous article that antennas are used in wireless communication in order to transmit the signal in the form of waves. It is designed to change electrical energy into the electromagnetic signals at the transmitting end. While electromagnetic signal back to electrical one at the receiving end.

So, it basically integrates the electric field and magnetic field in order to generate voltage and current so as to actuate electrical devices. Thus the antenna impedance at a point is also given as the ratio of electric field to the magnetic field at that particular point.

Hence we can say that the impedance provided by the antenna at its input terminal is known as antenna impedance.

We know that when a certain voltage is provided to any transmitting antenna then it generates current by following ohm’s law.

eq2

Here R represents the resistance of the input terminal of the antenna.

Further on considering the imaginary part, we will have

eq3

So, if we have a transmitting antenna that is radiating some power then impedance Z will be present behind it. This is known as the impedance of the antenna.

This impedance is a merger of resistance and reactance thereby forming a complex value.

Antenna Resistance

Suppose we have an antenna with input terminals x and y:

antenna

The power radiated by the input terminal of the antenna is given as:eq4

Since the total input power is the sum of radiated power and power loss,

Thus we can write it as:eq5

This is so because all the supplied power is not radiated as some amount of power is lost.

Hence the radiated power will be:eq6

While loss / dissipated power will be:eq7

On substituting the obtained value of Pr and PL in eq 1, we will have:eq8

Also putting the value of Pin we will haveeq9

As the total current will be the sum of radiation current and loss current. Therefore writing the above equation as:

eq10

On simplifying

eq11

Thus we can say that the input resistance will be the sum of radiation resistance and the loss resistance. Therefore the figure below represents the input impedance of antenna:

equivalent impedance of antenna

Derivation of supplied power to the Antenna

Suppose we have a configuration given below:

antenna input impedance

Here the two input terminals x and y of the antenna are connected across a generator.

One must note here that the generator will also have some internal impedance. So, consider the impedance of the generator be Zg.

We know that the impedance is given as:

eq12

Therefore

eq13

  • Here Rg denotes the resistance of the generator
  • While Xg denotes reactance of the generator

So, drawing the equivalent circuit of the generator antenna configuration given above:

thevenin's equivalent of antenna in transmitting mode

For transmitting antenna, the impedance will be given as

eq14

  • Here ZA is the impedance of the antenna,
  • RA is the antenna resistance,
  • XA denotes antenna reactance

The resistive part of the antenna which we have already derived is given as:

eq15

Let us now consider the Thevenin’s equivalent circuit shown above in order to determine the power delivered to Rr for radiation and the power dissipated in the form of heat in RL.

So, firstly we need to determine the current within the loop itself,

Therefore, by ohm’s laweq16

Here Vg is the maximum generator voltage while Zt denotes the total impedance present in the loop. Thuseq17

Further on simplifying,eq18

Since RA = Rr + RL

Therefore, we will have

eq19

Further

eq20

So, considering the magnitude form

eq21

Thus we can say the radiation power Pr will be

eq22

So, on substituting the value of Ig

eq23
Thus the power by the generator to the antenna for radiation will be

eq24

The dissipated power

eq25

Therefore

eq26

Also, the power dissipated on the internal resistance of the generator will be given as:

eq27

 The condition of maximum delivered power to the antenna is achievable in case of conjugate matching. This means

eq28

So, we will have

eq29 Similarly

eq30

And

eq31

It is noteworthy here that the generated power must be equal to the sum of radiated power and the dissipated power in the form of heat.

eq32

So, on substituting

eq33

The supplied power by the generator

eq34

Therefore,

eq35

So, we can say the overall power generated by the generator is the sum of the power dissipated by the internal resistance of the generator and the power supplied to the antenna, in case of conjugate matching.

While, out of the overall power which is supplied to the antenna by the generator, a part is radiated utilizing radiation resistance, while the rest is dissipated in the form of heat. This dissipated power in the form of heat alters the efficiency of the antenna.

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